Calcule o termo central da $P.G. \hspace{0.3em} (3, \ x+2, \ 27)$.
Dados da P.G.:
$a_{p} = x + 2 = ?$
$a_{p-1} = 3$
$a_{p+1} = 27$
Aplicando a fórmula temos:
$a_{p} = \sqrt[]{a_{p-1} . a_{p+1}}$
$x + 2 = \sqrt[]{3 . 27}$
$x+2 = \sqrt[]{81}$
$x+2 = 9$
$x= 9 - 2$
$x = 7$
Sabemos que:
$a_{p} = x + 2$
$a_{p} = 7 + 2$
$a_{p} = 9$
9